LeetCode MySQL-620. Not Boring Movies

    AllenLi
    LeetCode MySQL

    Write an SQL query to report the movies with an odd-numbered ID and a description that is not “boring”.
    Return the result table ordered by rating in descending order.

    寫一個 SQL 查詢有關奇數和沒有「boring」描述的影片
依照百分比進行降冪排序結果。

    Table: Cinema

    +----------------+----------+
| Column Name    | Type     |
+----------------+----------+
| id             | int      |
| movie          | varchar  |
| description    | varchar  |
| rating         | float    |
+----------------+----------+
id is the primary key for this table.
Each row contains information about the name of a movie, its genre, and its rating.
rating is a 2 decimal places float in the range [0, 10]

    Example 1:

    Input: 
Cinema table:
+----+------------+-------------+--------+
| id | movie      | description | rating |
+----+------------+-------------+--------+
| 1  | War        | great 3D    | 8.9    |
| 2  | Science    | fiction     | 8.5    |
| 3  | irish      | boring      | 6.2    |
| 4  | Ice song   | Fantacy     | 8.6    |
| 5  | House card | Interesting | 9.1    |
+----+------------+-------------+--------+
Output: 
+----+------------+-------------+--------+
| id | movie      | description | rating |
+----+------------+-------------+--------+
| 5  | House card | Interesting | 9.1    |
| 1  | War        | great 3D    | 8.9    |
+----+------------+-------------+--------+
Explanation: 
We have three movies with odd-numbered IDs: 1, 3, and 5. The movie with ID = 3 is boring so we do not include it in the answer.

    Solution:
    1. 選擇標題 id, movie, description, rating。
    2. 來自 Cinema 的 table。
    3. 尋找 description 的字符中前後沒有’boring’。
    4. 且 id % 2 的餘數為 1。(找奇數)
    5. 依照 rating 做降冪排序。

    Code.1:

    SELECT id, movie, description, rating
    FROM Cinema
    WHERE (description NOT LIKE 'boring%' OR '%boring')
		AND id % 2 = 1
ORDER BY rating DESC;

    newCinema

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