LeetCode MySQL-1527. Patients With a Condition

    LeetCode MySQL

    Write an SQL query to report the patient_id, patient_name all conditions of patients who have Type I Diabetes. Type I Diabetes always starts with DIAB1 prefix
    Return the result table in any order.

    寫一個 SQL Query來報告 I型糖料病患者。(ex. I型糖尿病患者為DIAB1開頭)
    可任意排序結果。
    

    Table: Patients

    +--------------+---------+
    | Column Name  | Type    |
    +--------------+---------+
    | patient_id   | int     |
    | patient_name | varchar |
    | conditions   | varchar |
    +--------------+---------+
    patient_id is the primary key for this table.
    'conditions' contains 0 or more code separated by spaces. 
    This table contains information of the patients in the hospital.
    

    Example 1:

    Input: 
    Patients table:
    +------------+--------------+--------------+
    | patient_id | patient_name | conditions   |
    +------------+--------------+--------------+
    | 1          | Daniel       | YFEV COUGH   |
    | 2          | Alice        |              |
    | 3          | Bob          | DIAB100 MYOP |
    | 4          | George       | ACNE DIAB100 |
    | 5          | Alain        | DIAB201      |
    +------------+--------------+--------------+
    Output: 
    +------------+--------------+--------------+
    | patient_id | patient_name | conditions   |
    +------------+--------------+--------------+
    | 3          | Bob          | DIAB100 MYOP |
    | 4          | George       | ACNE DIAB100 | 
    +------------+--------------+--------------+
    Explanation: Bob and George both have a condition that starts with DIAB1.
    

    Solution:
    1. 確認標題 * 。
    2. 來自 Patients 的 table。
    3. conditions中符合 ‘% DIAB1%’ or ‘DIAB1%’。
    (ex.確保為 DIAB1% 的字樣)

    Code.1:

    SELECT * FROM Patients
    WHERE conditions LIKE '% DIAB1%'
    	OR conditions LIKE 'DIAB1%';
    

    newPatients