LeetCode MySQL-1050. Actors and Directors Who Cooperated At Least Three Times

    AllenLi
    LeetCode MySQL

    Write a SQL query for a report that provides the pairs (actor_id, director_id) where the actor has cooperated with the director at least three times.
    Return the result table in any order.

    寫一個 SQL Query來報告有提供演員和導演至少合作三次的組合。
可任意排序結果。

    Table: ActorDirector

    +-------------+---------+
| Column Name | Type    |
+-------------+---------+
| actor_id    | int     |
| director_id | int     |
| timestamp   | int     |
+-------------+---------+
timestamp is the primary key column for this table.

    Example 1:

    Input: 
ActorDirector table:
+-------------+-------------+-------------+
| actor_id    | director_id | timestamp   |
+-------------+-------------+-------------+
| 1           | 1           | 0           |
| 1           | 1           | 1           |
| 1           | 1           | 2           |
| 1           | 2           | 3           |
| 1           | 2           | 4           |
| 2           | 1           | 5           |
| 2           | 1           | 6           |
+-------------+-------------+-------------+
Output: 
+-------------+-------------+
| actor_id    | director_id |
+-------------+-------------+
| 1           | 1           |
+-------------+-------------+
Explanation: The only pair is (1, 1) where they cooperated exactly 3 times.

    Solution:
    1. 確認標題 actor_id, director_id。
    2. 來自 ActorDirector 的 table。
    3. 以 actor_id 與 director_id 為群組。
    4. 有群組次數大於等於3。

    Code.1:

    SELECT actor_id, director_id
    FROM ActorDirector
GROUP BY actor_id, director_id
HAVING COUNT(*) >= 3;

    newActorDirector

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