LeetCode MySQL-1795. Rearrange Products Table

    LeetCode MySQL

    Write an SQL query to rearrange the Products table so that each row has (product_id, store, price). If a product is not available in a store, do not include a row with that product_id and store combination in the result table.
    Return the result table in any order.

    寫一個 SQL Query來重新排列 Products 表,讓每一行都有(product_id, store, price)項目。如果商店沒有產品的話,則不需放入。
    可任意排序結果。
    

    Table: Products

    +-------------+---------+
    | Column Name | Type    |
    +-------------+---------+
    | product_id  | int     |
    | store1      | int     |
    | store2      | int     |
    | store3      | int     |
    +-------------+---------+
    product_id is the primary key for this table.
    Each row in this table indicates the product's price in 3 different stores: store1, store2, and store3.
    If the product is not available in a store, the price will be null in that store's column.
    

    Example 1:

    Input: 
    Products table:
    +------------+--------+--------+--------+
    | product_id | store1 | store2 | store3 |
    +------------+--------+--------+--------+
    | 0          | 95     | 100    | 105    |
    | 1          | 70     | null   | 80     |
    +------------+--------+--------+--------+
    Output: 
    +------------+--------+-------+
    | product_id | store  | price |
    +------------+--------+-------+
    | 0          | store1 | 95    |
    | 0          | store2 | 100   |
    | 0          | store3 | 105   |
    | 1          | store1 | 70    |
    | 1          | store3 | 80    |
    +------------+--------+-------+
    Explanation: 
    Product 0 is available in all three stores with prices 95, 100, and 105 respectively.
    Product 1 is available in store1 with price 70 and store3 with price 80. The product is not available in store2.
    

    Solution:
    1. 選擇 * 列表。
    2. 篩選 product_id、store的名稱、store的價錢。
    3. 且 price 不為 NULL。

    Code.1:

    SELECT * FROM 
    (	
        SELECT product_id, 'store1' store, store1 AS price FROM Products
        UNION
        SELECT product_id, 'store2' store, store2 AS price FROM Products
        UNION
        SELECT product_id, 'store3' store, store3 AS price FROM Products
    ) AS T
    WHERE price IS NOT NULL
    ORDER BY product_id;
    

    newProducts